What is the pH of a 0.0123 mol L-1 solution of CH3COOH whose
Ka is 1.8 x 10-5 ?
Solution:
[H+] = _(Ka x M)
= _(1.8 10-5 x 0.0123)
= 4.71 x 10-4
pH = - log10(4.71 x 10-4)
= 3.33